[LeetCode] 88. Merge Sorted Array
Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.
Note:
You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2. The number of elements initialized in nums1 and nums2 are m and n respectively.
You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2. The number of elements initialized in nums1 and nums2 are m and n respectively.
Thought process:
Start from the ends of two arrays and merge to the end of nums1.
Solution:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 | public class Solution { public void merge(int[] nums1, int m, int[] nums2, int n) { int i = m - 1; int j = n - 1; while (i >= 0 && j >= 0) { if (nums1[i] > nums2[j]) { nums1[i + j + 1] = nums1[i]; i--; } else { nums1[i + j + 1] = nums2[j]; j--; } } if (j >= 0) { for (; j >= 0; j--) { nums1[j] = nums2[j]; } } } } |
Time complexity: O(m + n).
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